We solve the equations in the previous paragraph for a pressure of
(M1.4@33300ft.), and this gives an optimum 
of 
. This is way to
much, this figure we could never reach. Instead we look at what minimum
wingloding there is that still would allow us to travel at M1.4 without
using the afterburner(s). Since we know the T/W ratio (the weight
fractions leading up to the supercruise weight applied to 
), we can
calculate what L/D we can accept.
and
From this we can solve the minimum allowed W/S to be 
(drag koefficient
and K is calculated below)